This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1888. Excerpt: ... ning, and greater at the end of the stroke, than it would be in case the same steam was used in the low-pressure cylinder, with the same measure of expansion. Assuming the steam to be used without expansion, in the high-pressure cylinder, the measure of expansion is, obviously, the ratio of the volume of the low-pressure cylinder to that of the high-pressure cylinder. Let us now trace the component and resultant total pressures on the two pistons during a complete stroke of both. For this purpose let the stroke be separated into ten equal parts. Let V = volume of the high-pressure cylinder. 'IV = volume of the low-pressure cylinder. = measure of expansion. P--the total steam pressure on the steam side of the high-pressure piston. P, = resultant pressure on both pistons. Then, neglecting the volume of steam in the passages, and taking the pistons at the beginning of a stroke from right to left, we have the following component pressures: On the right of the //. /. P. "" left """-P. "" right"" 3 P. P,-3 P. Second--Take the pistons at 0.1 of their stroke. The steam which previously filled the h. p. cyl., now fills ninetenths of the //. p. cyl. and one-tenth of the /./. cyl. The total volume of the exhaust from the h. p. cyl. is now, therefore, 0.5) V + 0.1 x 3 V = 1.2 K; and its tension is j of its original tension. In this position, then, we have the following component pressures: On the right of the h. p. p., P. "" left "" "-HP-"" right" " /././., 3 x p. P,=.P= 27 P. Third--Take the pistons at 0.2 of their stroke. The volume of the exhaust steam from the //./. cyl. is now 0.8 V + 0.2 x 3 V = 1.4 V; and its tension is of its original tension. The component pressures will therefore be as follows: On the right of the h.p.p., P. "" left """-% P. "" right" "/....
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